The compound $\mathrm{A}, \mathrm{C}_8 \mathrm{H}_8 \mathrm{O}_2$ reacts with acetophenone to form a single product via cross-Aldol condensation. The compound A on reaction with conc. NaOH forms a substituted benzyl alcohol as one of the two products. The compound A is :
$$ \text { Match the LIST-I with LIST-II } $$
| List-I Reagents | List-II Name of Reaction involving carbonyl compounds | ||
| A. | I. | Tollen's Test | |
| B. | II. | Clemmensen Reduction | |
| C. | Aq. |
III. | Wolff - Kishner Reduction |
| D. | IV. | Fehling's Test | |
Choose the correct answer from the options given below :
Match List - I with List - II.
| List – I Reagents |
List – II Reaction Name (Involving aldehydes) |
|---|---|
|
A. H2, Pd–BaSO4 B. SnCl2, HCl C. CrO2Cl2, CS2 D. CO, HCl, Anhyd. AlCl3 |
I. Etard Reaction II. Rosenmund Reduction III. Gattermann–Koch Reaction IV. Stephen Reaction |
Choose the correct answer from the options given below :
Statement I : Compound (X), shown below, dissolves in NaHCO3 solution and has two chiral carbon atoms
Statement II : Compound (Y), shown below, has two carbons with sp3 hybridization, one carbon with sp2 and one carbon with sp hybridization
In the light of the above statements, choose the correct answer from the options given below :
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