Consider the following reactions. From these reactions which reaction will give carboxylic acid as a major product ?

(A) $\quad \mathrm{R}-\mathrm{C} \equiv \mathrm{N} \xrightarrow[\text { mild condition }]{\text { (i) } \stackrel{+}{\mathrm{H}} / \mathrm{H}_2 \mathrm{O}}$

(B) $\quad \mathrm{R}-\mathrm{MgX} \xrightarrow[\text { (ii) } \mathrm{H}_3 \mathrm{O}^{+}]{\text {(i) } \mathrm{CO}_2}$

(C) $\mathrm{R}-\mathrm{C} \equiv \mathrm{N} \xrightarrow[\text { (ii) } \mathrm{H}_3 \mathrm{O}^{+}]{\text {(i) } \mathrm{SnCl}_2 / \mathrm{HCl}}$

(D) $\quad \mathrm{R} \cdot \mathrm{CH}_2 \cdot \mathrm{OH} \xrightarrow{\mathrm{PCC}}$

(E)

Choose the correct answer from the options given below :

Given below are two statements:

Statement I : Vanilin will react with NaOH and also with Tollen's reagent.

Statement II : Vanilin will undergo self aldol condensation very easily.

In the light of the above statements, choose the most appropriate answer from the options given below :

An optically active alkyl halide $\mathrm{C}_4 \mathrm{H}_9 \mathrm{Br}[\mathrm{A}]$ reacts with hot KOH dissolved in ethanol and forms alkene $[B]$ as major product which reacts with bromine to give dibromide $[C]$. The compound [C] is converted into a gas [D] upon reacting with alcoholic $\mathrm{NaNH}_2$. During hydration 18 gram of water is added to 1 mole of gas [D] on warming with mercuric sulphate and dilute acid at 333 K to form compound [E]. The IUPAC name of compound [ E ] is :

The product (P) formed in the following reaction is :