1
JEE Main 2023 (Online) 31st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Cyclohexylamine when treated with nitrous acid yields $(\mathrm{P})$. On treating $(\mathrm{P})$ with $\mathrm{PCC}$ results in (Q). When $(\mathrm{Q})$ is heated with dil. $\mathrm{NaOH}$ we get $(\mathrm{R})$ The final product (R) is :
A
JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 45 English Option 1
B
JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 45 English Option 2
C
JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 45 English Option 3
D
JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 45 English Option 4
2
JEE Main 2023 (Online) 31st January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider the following reaction

JEE Main 2023 (Online) 31st January Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 42 English

The correct statement for product B is. It is

A
racemic mixture and is neutral
B
optically active and adds one mole of bromine
C
racemic mixture and gives a gas with saturated $$\mathrm{NaHCO}_{3}$$ solution
D
optically active alcohol and is neutral
3
JEE Main 2023 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: JEE Main 2023 (Online) 30th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 41 English 1 can be easily reduced using $\mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}$ to JEE Main 2023 (Online) 30th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 41 English 2

Reason $\mathrm{R}: \mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}$ is used to reduce carbonyl group to $-\mathrm{CH}_{2}-$ group.

In the light of the above statements, choose the correct answer from the options given below:
A
${ \text {Both } A \text { and }} \mathrm{R}$ are true and $\mathrm{R}$ is the correct explanation of $\mathrm{A}$
B
$\mathrm{A}$ is false but $\mathrm{R}$ is true
C
A is true but $\mathrm{R}$ is false
D
Both $\mathrm{A}$ and $\mathrm{R}$ are true but $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$
4
JEE Main 2023 (Online) 30th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

What is the correct order of acidity of the protons marked $$\mathrm{A}-\mathrm{D}$$ in the given compounds ?

JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 38 English

A
$$\mathrm{H}_{\mathrm{D}}>\mathrm{H}_{\mathrm{C}}>\mathrm{H}_{\mathrm{B}}>\mathrm{H}_{\mathrm{A}}$$
B
$$\mathrm{H}_{\mathrm{C}}>\mathrm{H}_{\mathrm{A}}>\mathrm{H}_{\mathrm{D}}>\mathrm{H}_{\mathrm{B}}$$
C
$$\mathrm{H}_{\mathrm{C}}>\mathrm{H}_{\mathrm{D}}>\mathrm{H}_{\mathrm{B}}>\mathrm{H}_{\mathrm{A}}$$
D
$$\mathrm{H}_{\mathrm{C}}>\mathrm{H}_{\mathrm{D}}>\mathrm{H}_{\mathrm{A}}>\mathrm{H}_{\mathrm{B}}$$
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