AIEEE 2009 | Aldehydes, Ketones and Carboxylic Acids Question 209 | Chemistry

In Cannizzaro reaction given below
2PhCHO $$\buildrel {\mathop {:OH}\limits^{\left( - \right)} } \over \longrightarrow $$ PhCH₂OH + $$PhC\mathop O\limits^{..} $$₂^(-)
the slowest step is :

the transfer of hydride to the carbonyl group

the abstraction of proton from the carboxylic group

the attack of $$:\mathop {OH}\limits^{( - )} $$ at the carboxyl group

the deprotonation of Ph CH₂OH

AIEEE 2007

MCQ (Single Correct Answer)

-1

The compound formed as a result of oxidation of ethyl benzene by KMnO₄ is :

benzophenone

acetophenone

benzoic acid

benzyl alcohol

AIEEE 2006

MCQ (Single Correct Answer)

-1

The increasing order of the rate of HCN addition to compounds A – D is
(A) HCHO
(B) CH₃COCH₃
(C) PhCOCH₃
(D) PhCOPh

A < B < C < D

D < B < C < A

D < C < B < A

C < D < B < A

AIEEE 2006

MCQ (Single Correct Answer)

-1

The correct order of increasing acid strength of the compounds

AIEEE 2006 Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 198 English

AIEEE 2006 Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 198 English

$$D < A < B < C$$

$$A < D < B < C$$

$$B < D < A < C$$

$$D < A < C < B$$

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