Given below are two statements:

Statement I : Vanilin will react with NaOH and also with Tollen's reagent.

Statement II : Vanilin will undergo self aldol condensation very easily.

In the light of the above statements, choose the most appropriate answer from the options given below :

An optically active alkyl halide $\mathrm{C}_4 \mathrm{H}_9 \mathrm{Br}[\mathrm{A}]$ reacts with hot KOH dissolved in ethanol and forms alkene $[B]$ as major product which reacts with bromine to give dibromide $[C]$. The compound [C] is converted into a gas [D] upon reacting with alcoholic $\mathrm{NaNH}_2$. During hydration 18 gram of water is added to 1 mole of gas [D] on warming with mercuric sulphate and dilute acid at 333 K to form compound [E]. The IUPAC name of compound [ E ] is :

The product (P) formed in the following reaction is :

The total number of compounds from below when treated with hot KMnO₄, giving benzoic acid is: