AIEEE 2005 | Ionic Equilibrium Question 104 | Chemistry

The molar solubility (in ol L^-1) of a sparingly soluble salt MX₄ is "s". The corresponding solubility product is K_sp. 's' is given in term of K_sp by the relation :

s = (256 K_sp)^1/5

s = (128 K_sp)^1/4

s = ( K_sp / 128)^1/4

s = (K_sp / 256)^1/5

AIEEE 2003

MCQ (Single Correct Answer)

-1

The solubility in water of a sparingly soluble salt AB₂ is 1.0 $$\times$$ 10^-5 mol L^-1. Its solubility product number will be :

4 $$\times$$ 10^-10

1 $$\times$$ 10^-15

1 $$\times$$ 10^-10

4 $$\times$$ 10^-15

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