JEE Main 2018 (Offline) | Ionic Equilibrium Question 85 | Chemistry

An aqueous solution contains 0.10 M H₂S and 0.20 M HCl. If the equilibrium constants for the formation of HS^– from H₂S is 1.0 $$\times$$ 10^–7 and that of S^2- from HS^– ions is 1.2 $$\times$$ 10^–13 then the concentration of S^2- ions in aqueous solution is :

5 $$\times$$ 10^–19

5 $$\times$$ 10^–8

3 $$\times$$ 10^–20

6 $$\times$$ 10^–21

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MCQ (Single Correct Answer)

-1

Following four solutions are prepared by mixing different volumes of NaOH and HCl of different concentrations, pH of which one of them will be equal to 1 ?

100 mL $${M \over {10}}$$ HCl + 100 mL $${M \over {10}}$$ NaOH

75 mL $${M \over {5}}$$ HCl + 25 mL $${M \over {5}}$$ NaOH

60 mL $${M \over {10}}$$ HCl + 40 mL $${M \over {10}}$$ NaOH

55 mL $${M \over {10}}$$ HCl + 45 mL $${M \over {10}}$$ NaOH

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MCQ (Single Correct Answer)

-1

Which of the following is a Lewis acid?

PH₃

B(CH₃)₃

NaH

NF₃

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MCQ (Single Correct Answer)

-1

The minimum volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution (K_sp of PbCl₂ = 3.2 $$ \times $$ 10^-8 atomic mass of Pb = 207 u ) is :

0.36 L

17.98 L

0.18 L

1.798 L

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