JEE Main 2019 (Online) 10th January Morning Slot | Ionic Equilibrium Question 78 | Chemistry

A mixture of 100 m mol of Ca(OH)₂ and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. The mass of calcium sulphate formed and the concentration of OH^– in resulting solution, respectively, are : (Molar mass of Ca (OH)₂, Na₂SO₄ and CaSO₄ are 74, 143 and 136 g mol^–1 , respectively; K_sp of Ca(OH)₂ is 5.5 × 10^–6 )

13.6g, 0.28 mol L^$$-$$1

13.6g, 0.14 mol L^$$-$$1

1.9g, 0.28 mol L^$$-$$1

1.9g, 0.14 mol L^$$-$$1

JEE Main 2019 (Online) 9th January Evening Slot

MCQ (Single Correct Answer)

-1

The pH of rain water, is approximately :

5.6

7.5

7.0

6.5

JEE Main 2019 (Online) 9th January Morning Slot

MCQ (Single Correct Answer)

-1

20 mL of 0.1 M H₂SO₄ solution is added to 30 mL of of 0.2 M NH₄OH solution. The pH of the resultant mixture is : [pk_b of NH₄OH = 4.7].

5.2

9.0

5.0

9.4

JEE Main 2018 (Offline)

MCQ (Single Correct Answer)

-1

An aqueous solution contains an unknown concentration of Ba²⁺. When 50 mL of a 1 M solution of Na₂SO₄ is added, BaSO₄ just begins to precipitate. The final volume is 500 mL. The solubility product of BaSO₄ is 1 $$\times$$ 10^–10. What is the original concentration of Ba²⁺?

1.0 $$\times$$ 10^–10 M

5 $$\times$$ 10^–9 M

2 $$\times$$ 10^–9 M

1.1 $$\times$$ 10^–9 M

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