JEE Main 2018 (Online) 15th April Evening Slot | Ionic Equilibrium Question 86 | Chemistry

Following four solutions are prepared by mixing different volumes of NaOH and HCl of different concentrations, pH of which one of them will be equal to 1 ?

100 mL $${M \over {10}}$$ HCl + 100 mL $${M \over {10}}$$ NaOH

75 mL $${M \over {5}}$$ HCl + 25 mL $${M \over {5}}$$ NaOH

60 mL $${M \over {10}}$$ HCl + 40 mL $${M \over {10}}$$ NaOH

55 mL $${M \over {10}}$$ HCl + 45 mL $${M \over {10}}$$ NaOH

JEE Main 2018 (Online) 15th April Morning Slot

MCQ (Single Correct Answer)

-1

Which of the following is a Lewis acid?

PH₃

B(CH₃)₃

NaH

NF₃

JEE Main 2018 (Online) 15th April Morning Slot

MCQ (Single Correct Answer)

-1

The minimum volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution (K_sp of PbCl₂ = 3.2 $$ \times $$ 10^-8 atomic mass of Pb = 207 u ) is :

0.36 L

17.98 L

0.18 L

1.798 L

JEE Main 2017 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :

3.75

4.75

8.25

9.25