1
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The stoichiometry and solubility product of a salt with the solubility curve given below is, respectively : JEE Main 2020 (Online) 8th January Morning Slot Chemistry - Ionic Equilibrium Question 67 English
A
XY, 2 × 10–6 M3
B
XY2, 1 × 10–9 M3
C
XY2, 4 × 10–9 M3
D
X2Y, 2 × 10–9 M3
2
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The strength of an aqueous NaOH solution is most accurately determined by titrating :
(Note : consider that an appropriate indicator is used)
A
Aq. NaOH in a pipette and aqueous oxalic acid in a burette
B
Aq. NaOH in a burette and aqueous oxalic acid in a conical flask
C
Aq. NaOH in a volumetric flask and concentrated H2SO4 in a conical flask
D
Aq. NaOH in a burette and concentrated H2SO4 in a conical flask
3
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The decreasing order of electrical conductivity of the following aqueous solutions is :

0.1 M Formic acid (A),

0.1 M Acetic acid (B),

0.1 M Benzoic acid (C)
A
A > B > C
B
C > B > A
C
A > C > B
D
C > A > B
4
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The molar solubility of Cd(OH)2 is 1.84 × 10–5 M in water. The expected solubility of Cd(OH)2 in a buffer solution of pH = 12 is :
A
2.49 × 10–10 M
B
1.84 × 10–9 M
C
6.23 × 10–11 M
D
$${{2.49} \over {1.84}} \times {10^{ - 9}}M$$
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