AIEEE 2005 | Rotational Motion Question 252 | Physics

The moment of inertia of a uniform semicircular disc of mass $$M$$ and radius $$r$$ about a line perpendicular to the plane of the disc through the center is

$${2 \over 5}M{r^2}$$

$${1 \over 4}Mr$$

$${1 \over 2}M{r^2}$$

$$M{r^2}$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

One solid sphere $$A$$ and another hollow sphere $$B$$ are of same mass and same outer radii. Their moment of inertia about their diameters are respectively $${I_A}$$ and $${I_B}$$ such that

$${I_A} < {I_B}$$

$${I_A} > {I_B}$$

$${I_A} = {I_B}$$

$${{{I_A}} \over {{I_B}}} = {{{d_A}} \over {{d_B}}}$$ where $${d_A}$$ and $${d_B}$$ are their densities.

AIEEE 2004

MCQ (Single Correct Answer)

-1

A solid sphere is rotating in free space. If the radius of the sphere is increased keeping mass same which on of the following will not be affected ?

Angular velocity

Angular momentum

Moment of inertia

Rotational kinetic energy

AIEEE 2003

MCQ (Single Correct Answer)

-1

A circular disc $$X$$ of radius $$R$$ is made from an iron plate of thickness $$t,$$ and another disc $$Y$$ of radius $$4$$ $$R$$ is made from an iron plate of thickness $${t \over 4}.$$ Then the relation between the moment of inertia $${I_X}$$ and $${I_Y}$$ is

$${I_Y} = 32{I_X}$$

$${I_Y} = 16{I_X}$$

$${I_Y} = {I_X}$$

$${I_Y} = 64{I_X}$$

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