AIEEE 2009 | Rotational Motion Question 191 | Physics

A thin uniform rod of length $$l$$ and mass $$m$$ is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is $$\omega $$. Its center of mass rises to a maximum height of:

$${1 \over 6}\,\,{{l\omega } \over g}$$

$${1 \over 2}\,\,{{{l^2}{\omega ^2}} \over g}$$

$${1 \over 6}\,\,{{{l^2}{\omega ^2}} \over g}$$

$${1 \over 3}\,\,{{{l^2}{\omega ^2}} \over g}$$

AIEEE 2008

MCQ (Single Correct Answer)

-1

Consider a uniform square plate of side $$' a '$$ and mass $$'m'$$. The moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is

$${5 \over 6}m{a^2}$$

$${1 \over 12}m{a^2}$$

$${7 \over 12}m{a^2}$$

$${2 \over 3}m{a^2}$$

AIEEE 2007

MCQ (Single Correct Answer)

-1

A round uniform body of radius $$R,$$ mass $$M$$ and moment of inertia $$I$$ rolls down (without slipping) an inclined plane making an angle $$\theta $$ with the horizontal. Then its acceleration is

$${{g\,\sin \theta } \over {1 - M{R^2}/I}}$$

$${{g\,\sin \theta } \over {1 + I/M{R^2}}}$$

$${{g\,\sin \theta } \over {1 + M{R^2}/I}}$$

$${{g\,\sin \theta } \over {1 - I/M{R^2}}}$$

AIEEE 2007

MCQ (Single Correct Answer)

-1

Angular momentum of the particle rotating with a central force is constant due to

constant torque

constant force

constant linear momentum

zero torque