1
JEE Main 2025 (Online) 2nd April Evening Shift
MCQ (Single Correct Answer)
+4
-1
The moment of inertia of a circular ring of mass M and diameter r about a tangential axis lying in the plane of the ring is :
A
$\frac{3}{8} \mathrm{Mr}^2$
B
$2 \mathrm{Mr}^2$
C
$\frac{1}{2} \mathrm{Mr}^2$
D
$\frac{3}{2} \mathrm{Mr}^2$
2
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Moment of inertia of a rod of mass ' M ' and length ' L ' about an axis passing through its center and normal to its length is ' $\alpha$ '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :

A
$\alpha / 4$
B
$\alpha / 8$
C
$\alpha$
D
$\alpha / 2$
3
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A square Lamina OABC of length 10 cm is pivoted at ' $\mathrm{O}^{\prime}$. Forces act at Lamina as shown in figure. If Lamina remains stationary, then the magnitude of F is :

JEE Main 2025 (Online) 2nd April Morning Shift Physics - Rotational Motion Question 10 English

A
10 N
B
0 (zero)
C
10$\sqrt2$ N
D
20 N
4
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A cord of negligible mass is wound around the rim of a wheel supported by spokes with negligible mass. The mass of wheel is 10 kg and radius is 10 cm and it can freely rotate without any friction. Initially the wheel is at rest. If a steady pull of 20 N is applied on the cord, the angular velocity of the wheel, after the cord is unwound by 1 m , would be:

JEE Main 2025 (Online) 2nd April Morning Shift Physics - Rotational Motion Question 12 English

A
20 rad/s
B
30 rad/s
C
10 rad/s
D
0 rad/s
JEE Main Subjects
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12