1
JEE Main 2025 (Online) 3rd April Morning Shift
MCQ (Single Correct Answer)
+4
-1
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A force of 49 N acts tangentially at the highest point of a sphere (solid) of mass 20 kg , kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is

JEE Main 2025 (Online) 3rd April Morning Shift Physics - Rotational Motion Question 5 English

A

$$ 2.5 \mathrm{~m} / \mathrm{s}^2 $$

B

$$ 3.5 \mathrm{~m} / \mathrm{s}^2 $$

C

$$ 0.25 \mathrm{~m} / \mathrm{s}^2 $$

D

$$ 0.35 \mathrm{~m} / \mathrm{s}^2 $$

2
JEE Main 2025 (Online) 2nd April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
The moment of inertia of a circular ring of mass M and diameter r about a tangential axis lying in the plane of the ring is :
A
$\frac{3}{8} \mathrm{Mr}^2$
B
$2 \mathrm{Mr}^2$
C
$\frac{1}{2} \mathrm{Mr}^2$
D
$\frac{3}{2} \mathrm{Mr}^2$
3
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Moment of inertia of a rod of mass ' M ' and length ' L ' about an axis passing through its center and normal to its length is ' $\alpha$ '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :

A
$\alpha / 4$
B
$\alpha / 8$
C
$\alpha$
D
$\alpha / 2$
4
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A square Lamina OABC of length 10 cm is pivoted at ' $\mathrm{O}^{\prime}$. Forces act at Lamina as shown in figure. If Lamina remains stationary, then the magnitude of F is :

JEE Main 2025 (Online) 2nd April Morning Shift Physics - Rotational Motion Question 10 English

A
10 N
B
0 (zero)
C
10$\sqrt2$ N
D
20 N
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