AIEEE 2007 | Rotational Motion Question 192 | Physics

A round uniform body of radius $$R,$$ mass $$M$$ and moment of inertia $$I$$ rolls down (without slipping) an inclined plane making an angle $$\theta $$ with the horizontal. Then its acceleration is

$${{g\,\sin \theta } \over {1 - M{R^2}/I}}$$

$${{g\,\sin \theta } \over {1 + I/M{R^2}}}$$

$${{g\,\sin \theta } \over {1 + M{R^2}/I}}$$

$${{g\,\sin \theta } \over {1 - I/M{R^2}}}$$

AIEEE 2007

MCQ (Single Correct Answer)

-1

Angular momentum of the particle rotating with a central force is constant due to

constant torque

constant force

constant linear momentum

zero torque

AIEEE 2007

MCQ (Single Correct Answer)

-1

For the given uniform square lamina $$ABCD$$, whose center is $$O,$$ AIEEE 2007 Physics - Rotational Motion Question 184 English

$${I_{AC}} = \sqrt 2 \,\,{I_{EF}}$$

$$\sqrt 2 {I_{AC}} = {I_{EF}}$$

$${I_{AD}} = 3{I_{EF}}$$

$${I_{AC}} = {I_{EF}}$$

AIEEE 2006

MCQ (Single Correct Answer)

-1

A thin circular ring of mass $$m$$ and radius $$R$$ is rotating about its axis with a constant angular velocity $$\omega $$. Two objects each of mass $$M$$ are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with an angular velocity $$\omega ' = $$

$${{\omega \left( {m + 2M} \right)} \over m}$$

$${{\omega \left( {m - 2M} \right)} \over {\left( {m + 2M} \right)}}$$

$${{\omega m} \over {\left( {m + M} \right)}}$$

$${{\omega m} \over {\left( {m + 2M} \right)}}$$

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