1
JEE Main 2020 (Online) 8th January Morning Slot
+4
-1
Consider a uniform rod of mass M = 4m and length $$\ell$$ pivoted about its centre. A mass m moving with velocity v making angle $$\theta = {\pi \over 4}$$ to the rod's long axis collides with one end of the rod and sticks to it. The angular speed of the rod-mass system just after the collision is :
A
$${{3\sqrt 2 } \over 7}{v \over \ell }$$
B
$${3 \over 7}{v \over \ell }$$
C
$${3 \over {7\sqrt 2 }}{v \over \ell }$$
D
$${4 \over 7}{v \over \ell }$$
2
JEE Main 2020 (Online) 7th January Evening Slot
+4
-1
Mass per unit area of a circular disc of radius $$a$$ depends on the distance r from its centre as $$\sigma \left( r \right)$$ = A + Br . The moment of inertia of the disc about the axis, perpendicular to the plane and assing through its centre is:
A
$$2\pi {a^4}\left( {{A \over 4} + {{aB} \over 5}} \right)$$
B
$$\pi {a^4}\left( {{A \over 4} + {{aB} \over 5}} \right)$$
C
$$2\pi {a^4}\left( {{{aA} \over 4} + {B \over 5}} \right)$$
D
$$2\pi {a^4}\left( {{A \over 4} + {B \over 5}} \right)$$
3
JEE Main 2020 (Online) 7th January Morning Slot
+4
-1
The radius of gyration of a uniform rod of length $$l$$, about an axis passing through a point $${l \over 4}$$ away from the centre of the rod, and perpendicular to it, is :
A
$${1 \over 8}l$$
B
$${1 \over 4}l$$
C
$$\sqrt {{7 \over {48}}} l$$
D
$$\sqrt {{3 \over 8}} l$$
4
JEE Main 2020 (Online) 7th January Morning Slot
+4
-1
As shown in the figure, a bob of mass m is tied by a massless string whose other end portion is wound on a fly wheel (disc) of radius r and mass m. When released from rest the bob starts falling vertically. When it has covered a distance of h, the angular speed of the wheel will be:
A
$$r\sqrt {{3 \over {2gh}}}$$
B
$$r\sqrt {{3 \over {4gh}}}$$
C
$${1 \over r}\sqrt {{{4gh} \over 3}}$$
D
$${1 \over r}\sqrt {{{2gh} \over 3}}$$
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