AIEEE 2007 | Rotational Motion Question 246 | Physics

A round uniform body of radius $$R,$$ mass $$M$$ and moment of inertia $$I$$ rolls down (without slipping) an inclined plane making an angle $$\theta $$ with the horizontal. Then its acceleration is

$${{g\,\sin \theta } \over {1 - M{R^2}/I}}$$

$${{g\,\sin \theta } \over {1 + I/M{R^2}}}$$

$${{g\,\sin \theta } \over {1 + M{R^2}/I}}$$

$${{g\,\sin \theta } \over {1 - I/M{R^2}}}$$

AIEEE 2006

MCQ (Single Correct Answer)

-1

A force of $$ - F\widehat k$$ acts on $$O,$$ the origin of the coordinate system. The torque about the point $$(1, -1)$$ is AIEEE 2006 Physics - Rotational Motion Question 238 English

AIEEE 2006 Physics - Rotational Motion Question 238 English

$$F\left( {\widehat i - \widehat j} \right)$$

$$ - F\left( {\widehat i + \widehat j} \right)$$

$$F\left( {\widehat i + \widehat j} \right)$$

$$ - F\left( {\widehat i - \widehat j} \right)$$

AIEEE 2006

MCQ (Single Correct Answer)

-1

Four point masses, each of value $$m,$$ are placed at the corners of a square $$ABCD$$ of side $$l$$. The moment of inertia of this system about an axis passing through $$A$$ and parallel to $$BD$$ is

$$2m{l^2}$$

$$\sqrt 3 m{l^2}$$

$$3m{l^2}$$

$$m{l^2}$$

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