JEE Main 2022 (Online) 28th June Evening Shift | Rotational Motion Question 83 | Physics

JEE Main 2022 (Online) 28th June Evening Shift

MCQ (Single Correct Answer)

-1

A ball is spun with angular acceleration $$\alpha$$ = 6t² $$-$$ 2t where t is in second and $$\alpha$$ is in rads^$$-$$2. At t = 0, the ball has angular velocity of 10 rads^$$-$$1 and angular position of 4 rad. The most appropriate expression for the angular position of the ball is :

$${3 \over 2}{t^4} - {t^2} + 10t$$

$${{{t^4}} \over 2} - {{{t^3}} \over 3} + 10t + 4$$

$${{2{t^4}} \over 3} - {{{t^3}} \over 6} + 10t + 12$$

$$2{t^4} - {{{t^3}} \over 2} + 5t + 4$$

JEE Main 2022 (Online) 28th June Evening Shift

MCQ (Single Correct Answer)

-1

A $$\sqrt {34} $$ m long ladder weighing 10 kg leans on a frictionless wall. Its feet rest on the floor 3 m away from the wall as shown in the figure. If E_f and F_w are the reaction forces of the floor and the wall, then ratio of $${F_w}/{F_f}$$ will be :

(Use g = 10 m/s².)

JEE Main 2022 (Online) 28th June Evening Shift Physics - Rotational Motion Question 92 English

$${6 \over {\sqrt {110} }}$$

$${3 \over {\sqrt {113} }}$$

$${3 \over {\sqrt {109} }}$$

$${2 \over {\sqrt {109} }}$$

JEE Main 2022 (Online) 28th June Morning Shift

MCQ (Single Correct Answer)

-1

Match List-I with List-II

	List-I		List-II
(A)	Moment of inertia of solid sphere of radius R about any tangent.	(I)	$${5 \over 3}M{R^2}$$
(B)	Moment of inertia of hollow sphere of radius (R) about any tangent.	(II)	$${7 \over 5}M{R^2}$$
(C)	Moment of inertia of circular ring of radius (R) about its diameter.	(III)	$${1 \over 4}M{R^2}$$
(D)	Moment of inertia of circular disc of radius (R) about any diameter.	(IV)	$${1 \over 2}M{R^2}$$

Choose the correct answer from the options given below :

A - II, B - I, C - IV, D - III

A - I, B - II, C - IV, D - III

A - II, B - I, C - III, D - IV

A - I, B - II, C - III, D - IV

JEE Main 2022 (Online) 27th June Evening Shift

MCQ (Single Correct Answer)

-1

One end of a massless spring of spring constant k and natural length l₀ is fixed while the other end is connected to a small object of mass m lying on a frictionless table. The spring remains horizontal on the table. If the object is made to rotate at an angular velocity $$\omega$$ about an axis passing through fixed end, then the elongation of the spring will be :

$${{k - m{\omega ^2}{l_0}} \over {m{\omega ^2}}}$$

$${{m{\omega ^2}{l_0}} \over {k + m{\omega ^2}}}$$

$${{m{\omega ^2}{l_0}} \over {k - m{\omega ^2}}}$$

$${{k + m{\omega ^2}{l_0}} \over {m{\omega ^2}}}$$

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