JEE Main 2019 (Online) 11th January Evening Slot | Rotational Motion Question 120 | Physics

JEE Main 2019 (Online) 11th January Evening Slot

MCQ (Single Correct Answer)

-1

The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians) :

$${\pi \over 8}$$

$${\pi \over 6}$$

$${\pi \over 4}$$

$${\pi \over 3}$$

JEE Main 2019 (Online) 11th January Evening Slot

MCQ (Single Correct Answer)

-1

A circular disc D₁ of mass M and radius R has two identical discs D₂ and D₃ of the same mass M and radius R attached rigidly at its opposite ends (see figure). The moment of inertia of the system about the axis OO' ,passing through the centre of D₁ as shown in the figure, will be :

JEE Main 2019 (Online) 11th January Evening Slot Physics - Rotational Motion Question 122 English

JEE Main 2019 (Online) 11th January Evening Slot Physics - Rotational Motion Question 122 English

3MR²

MR²

$${2 \over 3}$$ MR²

$${4 \over 5}$$ MR²

JEE Main 2019 (Online) 11th January Evening Slot

MCQ (Single Correct Answer)

-1

A string is wound around a hollow cylinder of mass 5 kg and radius 0.5m. If the string is now pulled with a horizontal force of 40 N, and the cylinder is rolling without slipping on a horizontal surface (see figure), then the angular acceleration of the cylinder will be (Neglect the mass and thickness of the string) :

JEE Main 2019 (Online) 11th January Evening Slot Physics - Rotational Motion Question 121 English

JEE Main 2019 (Online) 11th January Evening Slot Physics - Rotational Motion Question 121 English

16 rad/s²

20 rad/s²

10 rad/s²

12 rad/s²

JEE Main 2019 (Online) 11th January Morning Slot

MCQ (Single Correct Answer)

-1

A particle is moving along a circular path with a constant speed of 10 ms^–1. What is the magnitude of the change in velocity of the particle, when it moves through an angle of 60^o around the centre of the circle?

zero

10 m/s

$$10\sqrt 2 m/s$$

$$10\sqrt 3 m/s$$

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