JEE Main 2022 (Online) 26th June Evening Shift | Rotational Motion Question 90 | Physics

A solid spherical ball is rolling on a frictionless horizontal plane surface about its axis of symmetry. The ratio of rotational kinetic energy of the ball to its total kinetic energy is

$${2 \over 5}$$

$${2 \over 7}$$

$${1 \over 5}$$

$${7 \over 10}$$

JEE Main 2022 (Online) 26th June Morning Shift

MCQ (Single Correct Answer)

-1

A thin circular ring of mass M and radius R is rotating with a constant angular velocity 2 rads^$$-$$1 in a horizontal plane about an axis vertical to its plane and passing through the center of the ring. If two objects each of mass m be attached gently to the opposite ends of a diameter of ring, the ring will then rotate with an angular velocity (in rads^$$-$$1).

$${M \over {(M + m)}}$$

$${{(M + 2m)} \over {2M}}$$

$${{2M} \over {(M + 2m)}}$$

$${{2(M + 2m)} \over M}$$

JEE Main 2022 (Online) 25th June Morning Shift

MCQ (Single Correct Answer)

-1

If force $$\overrightarrow F = 3\widehat i + 4\widehat j - 2\widehat k$$ acts on a particle position vector $$2\widehat i + \widehat j + 2\widehat k$$ then, the torque about the origin will be :

$$3\widehat i + 4\widehat j - 2\widehat k$$

$$ - 10\widehat i + 10\widehat j + 5\widehat k$$

$$10\widehat i + 5\widehat j - 10\widehat k$$

$$10\widehat i + \widehat j - 5\widehat k$$

JEE Main 2021 (Online) 31st August Evening Shift

MCQ (Single Correct Answer)

-1

A system consists of two identical spheres each of mass 1.5 kg and radius 50 cm at the end of light rod. The distance between the centres of the two spheres is 5 m. What will be the moment of inertia of the system about an axis perpendicular to the rod passing through its midpoint?

18.75 kgm²

1.905 $$\times$$ 10⁵ kgm²

19.05 kgm²

1.875 $$\times$$ 10⁵ kgm²

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