AIEEE 2003 | Rotational Motion Question 256 | Physics

Let $$\overrightarrow F $$ be the force acting on a particle having position vector $$\overrightarrow r ,$$ and $$\overrightarrow \tau $$ be the torque of this force about the origin. Then

$$\overrightarrow {r.} \overrightarrow \tau = 0\,\,$$ and $$\overrightarrow {F.} \overrightarrow \tau \ne 0\,\,$$

$$\overrightarrow {r.} \vec \tau \ne 0{\mkern 1mu} {\mkern 1mu} $$ and $$\overrightarrow {F.} \overrightarrow \tau = 0\,\,$$

$$\overrightarrow {r.} \vec \tau \ne 0{\mkern 1mu} $$ and $$\overrightarrow {F.} \overrightarrow \tau \ne 0$$

$$\overrightarrow {r.} \vec \tau = 0{\mkern 1mu} $$ and $$\overrightarrow {F.} \overrightarrow \tau = 0\,\,$$

AIEEE 2002

MCQ (Single Correct Answer)

-1

Moment of inertia of a circular wire of mass $$M$$ and radius $$R$$ about its diameter is

$${{M{R^2}} \over 2}$$

$$M{R^2}$$

$$2M{R^2}$$

$${{M{R^2}} \over 4}$$

AIEEE 2002

MCQ (Single Correct Answer)

-1

A solid sphere, a hollow sphere and a ring are released from top of an inclined plane (frictionless) so that they slide down the plane. Then maximum acceleration down the plane is for (no rolling)

solid sphere

hollow sphere

ring

all same

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