1
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
The decreasing order of electrical conductivity of the following aqueous solutions is :

0.1 M Formic acid (A),

0.1 M Acetic acid (B),

0.1 M Benzoic acid (C)
A
A > B > C
B
C > B > A
C
A > C > B
D
C > A > B
2
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
The molar solubility of Cd(OH)2 is 1.84 × 10–5 M in water. The expected solubility of Cd(OH)2 in a buffer solution of pH = 12 is :
A
2.49 × 10–10 M
B
1.84 × 10–9 M
C
6.23 × 10–11 M
D
$${{2.49} \over {1.84}} \times {10^{ - 9}}M$$
3
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
What is the molar solubility of Al(OH)3 in 0.2 M NaOH solution ? Given that, solubility product of Al(OH)3 = 2.4 × 10–24 :
A
3 × 10–22
B
3 × 10–19
C
12 × 10–21
D
12 × 10–22
4
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
The pH of a 0.02 M NH4Cl solution will be :
[given Kb (NH4OH) = 10–5 and log 2 = 0.301]
A
2.56
B
5.35
C
4.35
D
4.65
JEE Main Subjects
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
CBSE
Class 12