1
JEE Main 2022 (Online) 29th July Morning Shift
Numerical
+4
-1

The reaction between X and Y is first order with respect to X and zero order with respect to Y.

Experiment $${{[X]} \over {mol\,{L^{ - 1}}}}$$ $${{[Y]} \over {mol\,{L^{ - 1}}}}$$ $${{Initial\,rate} \over {mol\,{L^{ - 1}}\,{{\min }^{ - 1}}}}$$
I 0.1 0.1 $$2 \times {10^{ - 3}}$$
I L 0.2 $$4 \times {10^{ - 3}}$$
III 0.4 0.4 $$M \times {10^{ - 3}}$$
IV 0.1 0.2 $$2 \times {10^{ - 3}}$$

Examine the data of table and calculate ratio of numerical values of M and L. (Nearest Integer)

2
JEE Main 2022 (Online) 28th July Evening Shift
Numerical
+4
-1

For a reaction, given below is the graph of $$\ln k$$ vs $${1 \over T}$$. The activation energy for the reaction is equal to ____________ $$\mathrm{cal} \,\mathrm{mol}^{-1}$$. (nearest integer)

(Given : $$\mathrm{R}=2 \,\mathrm{cal} \,\mathrm{K}^{-1} \,\mathrm{~mol}^{-1}$$ )

3
JEE Main 2022 (Online) 28th July Morning Shift
Numerical
+4
-1

For the given first order reaction

$$\mathrm{A} \rightarrow \mathrm{B}$$

the half life of the reaction is $$0.3010 \mathrm{~min}$$. The ratio of the initial concentration of reactant to the concentration of reactant at time $$2.0 \mathrm{~min}$$ will be equal to ___________. (Nearest integer)

4
JEE Main 2022 (Online) 27th July Evening Shift
Numerical
+4
-1

$$\matrix{ {[A]} & \to & {[B]} \cr {{\mathop{\rm Reactant}\nolimits} } & {} & {{\mathop{\rm Product}\nolimits} } \cr }$$

If formation of compound $$[\mathrm{B}]$$ follows the first order of kinetics and after 70 minutes the concentration of $$[\mathrm{A}]$$ was found to be half of its initial concentration. Then the rate constant of the reaction is $$x \times 10^{-6} \mathrm{~s}^{-1}$$. The value of $$x$$ is ______________. (Nearest Integer)

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