1
JEE Main 2022 (Online) 28th June Morning Shift
Numerical
+4
-1

For a first order reaction A $$\to$$ B, the rate constant, k = 5.5 $$\times$$ 10$$-$$14 s$$-$$1. The time required for 67% completion of reaction is x $$\times$$ 10$$-$$1 times the half life of reaction. The value of x is _____________ (Nearest integer)

(Given : log 3 = 0.4771)

2
JEE Main 2022 (Online) 27th June Evening Shift
Numerical
+4
-1

It has been found that for a chemical reaction with rise in temperature by 9 K the rate constant gets doubled. Assuming a reaction to be occurring at 300 K, the value of activation energy is found to be ____________ kJ mol$$-$$1. [nearest integer]

(Given ln10 = 2.3, R = 8.3 J K$$-$$1 mol$$-$$1, log 2 = 0.30)

3
JEE Main 2022 (Online) 27th June Morning Shift
Numerical
+4
-1

The rate constant for a first order reaction is given by the following equation:

$$\ln k = 33.24 - {{2.0 \times {{10}^4}\,K} \over T}$$

The activation energy for the reaction is given by ____________ kJ mol$$-$$1. (In nearest integer) (Given : R = 8.3 J K$$-$$1 mol$$-$$1)

4
JEE Main 2022 (Online) 26th June Evening Shift
Numerical
+4
-1

Catalyst A reduces the activation energy for a reaction by 10 kJ mol$$-$$1 at 300 K. The ratio of rate constants, $${{{}^kT,\,Catalysed} \over {{}^kT,\,Uncatalysed}}$$ is ex. The value of x is ___________. [nearest integer]

[Assume that the pre-exponential factor is same in both the cases. Given R = 8.31 J K$$-$$1 mol$$-$$1]