1
JEE Main 2023 (Online) 24th January Morning Shift
Numerical
+4
-1
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The number of correct statement/s from the following is __________

A. Larger the activation energy, smaller is the value of the rate constant.

B. The higher is the activation energy, higher is the value of the temperature coefficient.

C. At lower temperatures, increase in temperature causes more change in the value of k than at higher temperature

D. A plot of $$\mathrm{\ln k}$$ vs $$\frac{1}{T}$$ is a straight line with slope equal to $$-\frac{E_a}{R}$$

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2
JEE Main 2022 (Online) 29th July Evening Shift
Numerical
+4
-1
Change Language

Assuming $$1 \,\mu \mathrm{g}$$ of trace radioactive element X with a half life of 30 years is absorbed by a growing tree. The amount of X remaining in the tree after 100 years is ______ $$\times\, 10^{-1} \mu \mathrm{g}$$.

[Given : ln 10 = 2.303; log 2 = 0.30]

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3
JEE Main 2022 (Online) 29th July Morning Shift
Numerical
+4
-1
Change Language

The reaction between X and Y is first order with respect to X and zero order with respect to Y.

Experiment $${{[X]} \over {mol\,{L^{ - 1}}}}$$ $${{[Y]} \over {mol\,{L^{ - 1}}}}$$ $${{Initial\,rate} \over {mol\,{L^{ - 1}}\,{{\min }^{ - 1}}}}$$
I 0.1 0.1 $$2 \times {10^{ - 3}}$$
I L 0.2 $$4 \times {10^{ - 3}}$$
III 0.4 0.4 $$M \times {10^{ - 3}}$$
IV 0.1 0.2 $$2 \times {10^{ - 3}}$$

Examine the data of table and calculate ratio of numerical values of M and L. (Nearest Integer)

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4
JEE Main 2022 (Online) 28th July Evening Shift
Numerical
+4
-1
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For a reaction, given below is the graph of $$\ln k$$ vs $${1 \over T}$$. The activation energy for the reaction is equal to ____________ $$\mathrm{cal} \,\mathrm{mol}^{-1}$$. (nearest integer)

(Given : $$\mathrm{R}=2 \,\mathrm{cal} \,\mathrm{K}^{-1} \,\mathrm{~mol}^{-1}$$ )

JEE Main 2022 (Online) 28th July Evening Shift Chemistry - Chemical Kinetics and Nuclear Chemistry Question 46 English

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