1
JEE Main 2026 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$$ \text { Match List - I with List - II. } $$

$$
\text { List - I }
$$
$$
\text { List - II }
$$
A. Meter (L) I. $$
\sqrt{\frac{h c}{G}}
$$
B. Second (S) II. $$
\sqrt{\frac{G h}{c^5}}
$$
C. Kilogram (M) III. $$
\sqrt{\frac{K^2 L^2 c^3}{G h}}
$$
D. Kelvin (K) IV. $$
\sqrt{\frac{G h}{c^3}}
$$

where h (Planck's constant), G (gravitational constant) and c (speed of light in vacuum) as fundamental units.

Choose the correct answer from the options given below :

A

A-II, B-IV, C-I, D-III

B

A-IV, B-II, C-I, D-III

C

A-IV, B-I, C-II, D-III

D

A-III, B-I, C-II, D-IV

2
JEE Main 2026 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In an experiment to determine the resistance of a given wire using Ohm's law, the voltmeter and ammeter readings are noted as 10 V and 5 A , respectively. The least counts of voltmeter and ammeter are 500 mV and 200 mA , respectively. The estimated error in the resistance measurement is $\_\_\_\_$ $\Omega$

A

0.25

B

2

C

2.5

D

0.18

3
JEE Main 2026 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A mass of 1 kg is kept on a inclined plane with $30^{\circ}$ inclination with respect to horizontal plane and it is at rest initially. Then the whole assembly is moved up with constant velocity of $4 \mathrm{~m} / \mathrm{s}$. The work done by the frictional force in time 2 s is $\_\_\_\_$ J. (Take $g=10 \mathrm{~m} / \mathrm{s}^2$ )

A

20

B

25

C

30

D

10

4
JEE Main 2026 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The velocity $(v)$ versus time $(t)$ plot of a particle is shown in the figure, for a time interval of 40 s . The total distance travelled by the particle and the average velocity during this period are, respectively

$\_\_\_\_$.

JEE Main 2026 (Online) 5th April Evening Shift Physics - Motion in a Straight Line Question 3 English
A

25 m and zero

B

50 m and zero

C

100 m and zero

D

100 m and $2.5 \mathrm{~m} / \mathrm{s}$

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