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JEE Main 2026 (Online) 28th January Evening Shift
MCQ (Single Correct Answer)
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The cyclic cations having the same number of hyperconjugation are :

JEE Main 2026 (Online) 28th January Evening Shift Chemistry - Basics of Organic Chemistry Question 24 English

Choose the correct answer from the options given below :

A

B and C Only

B

A and B Only

C

A and C Only

D

A, C and D only

2
JEE Main 2026 (Online) 28th January Evening Shift
Numerical
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The number of isoelectronic species among $Sc^{3+}, Cr^{2+}, Mn^{3+}, Co^{3+}$ and $Fe^{3+}$ is ‘n’. If ‘n’ moles of AgCl is formed during the reaction of complex with formula $CoCl_3(en)_2NH_3$ with excess of $AgNO_3$ solution, then the number of electrons present in the $t_{2g}$ orbital of the complex is ________.

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3
JEE Main 2026 (Online) 28th January Evening Shift
Numerical
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A volume of x mL of 5 M NaHCO3 solution was mixed with 10 mL of 2 M H2CO3 solution to make an electrolytic buffer. If the same buffer was used in the following electrochemical cell to record a cell potential of 235.3 mV, then the value of x = ______ mL (nearest integer).

Sn(s) | Sn(OH)62− (0.5 M) | HSnO2 (0.05 M) | OH | Bi2O3(s) | Bi(s)

Consider up to one place of decimal for intermediate calculations


$\left[\begin{array}{ll}\text { Given: } & E_{Sn\left( {OH} \right)_6^{2 - } |HSnO_2^ -}^o = - 0.9V \\ & \mathrm{E}^{\mathrm{o}}{ }_{\mathrm{Bi}_2 \mathrm{O}_3 \mid \mathrm{Bi}}=-0.44 \mathrm{~V} \\ & \mathrm{pKa}_{\left(\mathrm{H}_2 \mathrm{CO}_3\right)}=6.11 \\ & \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V} \\ & \text { Antilog }(1.29)=19.5\end{array}\right]$
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4
JEE Main 2026 (Online) 28th January Evening Shift
Numerical
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For strong electrolyte $\Lambda_m$ increases slowly with dilution and can be represented by the equation

$$\Lambda_m = \Lambda_m^\circ - A c^{1/2}$$

Molar conductivity values of the solutions of strong electrolyte AB at 18°C are given below :

c [mol L-1]0.040.090.160.25
$\Lambda_m$ [S cm2 mol-1]96.195.795.394.9

The value of constant A based on the above data [in S cm2 mol-1/(mol/L)1/2] unit is ________.

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