1
JEE Main 2026 (Online) 21st January Evening Shift
Numerical
+4
-1
Change Language

MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.

$\mathrm{MX}(\mathrm{s}) \rightleftharpoons \mathrm{M}^{+}(\mathrm{aq})+\mathrm{X}^{-}(\mathrm{aq}) ; \quad \mathrm{K}_{\mathrm{sp}}=10^{-10}$

If the standard reduction potential for M+ (aq) + e → M(s) is
$\left(\mathrm{E}_{\mathrm{M}^{+} / \mathrm{M}}^{\ominus}\right)=0.79 \mathrm{~V}$, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $\mathrm{E}_{\mathrm{X}^{-} / \mathrm{MX}(\mathrm{s}) / \mathrm{M}}^{\ominus}$ is ______ mV. (nearest integer)

[Given: $ \dfrac{2.303 RT}{F} = 0.059\ \text{V} $]

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2
JEE Main 2026 (Online) 21st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If the line $\alpha x+4 y=\sqrt{7}$, where $\alpha \in \mathbf{R}$, touches the ellipse $3 x^2+4 y^2=1$ at the point P in the first quadrant, then one of the focal distances of $P$ is :

A
$\frac{1}{\sqrt{3}}-\frac{1}{2 \sqrt{11}}$
B
$\frac{1}{\sqrt{3}}-\frac{1}{2 \sqrt{5}}$
C
$\frac{1}{\sqrt{3}}+\frac{1}{2 \sqrt{5}}$
D
$\frac{1}{\sqrt{3}}+\frac{1}{2 \sqrt{7}}$
3
JEE Main 2026 (Online) 21st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $\alpha$ and $\beta$ be the roots of the equation $x^2+2 a x+(3 a+10)=0$ such that $\alpha<1<\beta$. Then the set of all possible values of $a$ is :
A
$\left(-\infty, \frac{-11}{5}\right) \cup(5, \infty)$
B
$\left(-\infty, \frac{-11}{5}\right)$
C
$(-\infty,-3)$
D
$(-\infty,-2) \cup(5, \infty)$
4
JEE Main 2026 (Online) 21st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let $y^2 = 12x$ be the parabola with its vertex at $O$. Let $P$ be a point on the parabola and $A$ be a point on the $x$-axis such that $\angle OPA = 90^\circ$. Then the locus of the centroid of such triangles $OPA$ is:

A

$y^2 - 4x + 8 = 0$

B

$y^2 - 2x + 8 = 0$

C

$y^2 - 9x + 6 = 0$

D

$y^2 - 6x + 4 = 0$

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