Statement I : Compound (X), shown below, dissolves in NaHCO3 solution and has two chiral carbon atoms
Statement II : Compound (Y), shown below, has two carbons with sp3 hybridization, one carbon with sp2 and one carbon with sp hybridization
In the light of the above statements, choose the correct answer from the options given below :
A. Mn forms the oxide $\mathrm{Mn_2O_7}$, in which Mn is in its highest oxidation state.
B. Oxygen stabilizes the Mn in higher oxidation states by forming multiple bonds with Mn.
C. $\mathrm{Mn_2O_7}$ is an ionic oxide.
D. The structure of $\mathrm{Mn_2O_7}$ consists of one bridged oxygen.
Choose the correct answer from the options given below :
Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be :
Match List - I with List - II.
| List - I Pair of Compounds |
List - II Type of Isomers |
|---|---|
| A. 2-Methylpropene and but-1-ene | I. Stereoisomers |
| B. Cis-but-2-ene and trans-but-2-ene | II. Position isomers |
| C. 2-Butanol and diethyl ether | III. Chain isomers |
| D. But-1-ene and but-2-ene | IV. Functional group isomers |
Choose the correct answer from the options given below :
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