1
JEE Main 2025 (Online) 22nd January Morning Shift
Fill in the Blanks
+4
-1

Let $A$ be a square matrix of order 3 such that $\operatorname{det}(A)=-2$ and $\operatorname{det}(3 \operatorname{adj}(-6 \operatorname{adj}(3 A)))=2^{m+n} \cdot 3^{m n}, m>n$. Then $4 m+2 n$ is equal to __________.

2
JEE Main 2025 (Online) 22nd January Morning Shift
MCQ (Single Correct Answer)
+4
-1

A small point of mass $m$ is placed at a distance $2 R$ from the centre ' $O$ ' of a big uniform solid sphere of mass M and radius R . The gravitational force on ' m ' due to M is $\mathrm{F}_1$. A spherical part of radius $\mathrm{R} / 3$ is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of $M$ is found to be $F_2$. The value of ratio $F_1: F_2$ is

JEE Main 2025 (Online) 22nd January Morning Shift Physics - Gravitation Question 1 English

A
11 : 10
B
12 : 11
C
16 : 9
D
12 : 9
3
JEE Main 2025 (Online) 22nd January Morning Shift
MCQ (Single Correct Answer)
+4
-1

If $B$ is magnetic field and $\mu_0$ is permeability of free space, then the dimensions of $\left(B / \mu_0\right)$ is

A
$\mathrm{MT}^{-2} \mathrm{~A}^{-1}$
B
$\mathrm{L}^{-1} \mathrm{~A}$
C
$\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^{-1}$
D
$\mathrm{LT}^{-2} \mathrm{~A}^{-1}$
4
JEE Main 2025 (Online) 22nd January Morning Shift
MCQ (Single Correct Answer)
+4
-1

A uniform circular disc of radius ' $\mathrm{R}^{\prime}$ and mass ' $\mathrm{M}^{\prime}$ is rotating about an axis perpendicular to its plane and passing through its centre. A small circular part of radius $R / 2$ is removed from the original disc as shown in the figure. Find the moment of inertia of the remaining part of the original disc about the axis as given above.

JEE Main 2025 (Online) 22nd January Morning Shift Physics - Rotational Motion Question 1 English

A
$\frac{17}{32} \mathrm{MR}^2$
B
$\frac{13}{32} \mathrm{MR}^2$
C
$\frac{9}{32} \mathrm{MR}^2$
D
$\frac{7}{32} \mathrm{MR}^2$
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