1
JEE Main 2023 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements

Statement I : Area under velocity- time graph gives the distance travelled by the body in a given time.

Statement II : Area under acceleration- time graph is equal to the change in velocity- in the given time.

In the light of given statements, choose the correct answer from the options given below.

A
Both Statement I and Statement II are False.
B
Both Statement I and Statement II are true.
C
Statement I is incorrect but Statement II is true.
D
Statement I is correct but Statement II is false.
2
JEE Main 2023 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language

For a given transistor amplifier circuit in $$\mathrm{CE}$$ configuration $$\mathrm{V}_{\mathrm{CC}}=1 \mathrm{~V}, \mathrm{R}_{\mathrm{C}}=1 ~\mathrm{k} \Omega, \mathrm{R}_{\mathrm{b}}=100 ~\mathrm{k} \Omega$$ and $$\beta=100$$. Value of base current $$\mathrm{I}_{\mathrm{b}}$$ is

JEE Main 2023 (Online) 8th April Evening Shift Physics - Semiconductor Question 22 English

A
$$\mathrm{I}_{\mathrm{b}}=100 ~\mu \mathrm{A}$$
B
$$\mathrm{I}_{\mathrm{b}}=0.1 ~\mu \mathrm{A}$$
C
$$\mathrm{I}_{\mathrm{b}}=1.0 ~\mu \mathrm{A}$$
D
$$\mathrm{I}_{\mathrm{b}}=10 ~\mu \mathrm{A}$$
3
JEE Main 2023 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language

A radio active material is reduced to $$1 / 8$$ of its original amount in 3 days. If $$8 \times 10^{-3} \mathrm{~kg}$$ of the material is left after 5 days the initial amount of the material is

A
64 g
B
256 g
C
32 g
D
40 g
4
JEE Main 2023 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The acceleration due to gravity at height $$h$$ above the earth if $$h << \mathrm{R}$$ (Radius of earth) is given by

A
$$g^{\prime}=g\left(1-\frac{2 h}{R}\right)$$
B
$$g^{\prime}=g\left(1-\frac{2 h^{2}}{R^{2}}\right)$$
C
$$g^{\prime}=g\left(1-\frac{h^{2}}{2 R^{2}}\right)$$
D
$$g^{\prime}=g\left(1-\frac{h}{2 R}\right)$$
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