When $$\mathrm{Cu}^{2+}$$ ion is treated with $$\mathrm{KI}$$, a white precipitate, $$\mathrm{X}$$ appears in solution. The solution is titrated with sodium thiosulphate, the compound $$\mathrm{Y}$$ is formed. $$\mathrm{X}$$ and $$\mathrm{Y}$$ respectively are :

Match items of column I and II

	Column I (Mixture of compounds)		Column II (Separation Technique)
A.	$$\mathrm{H_2O/CH_2Cl_2}$$	i.	Crystalization
B.		ii.	Differential solvent extraction
C.	Kerosene / Naphthalene	iii.	Column chromatography
D.	$$\mathrm{C_6H_{12}O_6/NaCl}$$	iv.	Fractional Distillation

Correct match is

Consider the following reaction

The correct statement for product B is. It is

$$\mathrm{Nd^{2+}}$$ = __________