Match List-I with List-II.
List-I | List-II | ||
---|---|---|---|
(A) | I. | $$B{r_2}$$ in $$C{S_2}$$ | |
(B) | II. | $$N{a_2}C{r_2}{O_7}/{H_2}S{O_4}$$ | |
(C) | III. | $$Zn$$ | |
(D) | IV. | $$CHC{l_3}/NaOH$$ |
Choose the correct answer from the options given below :
Decarboxylation of all six possible forms of diaminobenzoic acids C6H3(NH2)2COOH yields three products A, B and C. Three acids give a product 'A', two acids gives a product 'B' and one acid give a product 'C'. The melting point of product 'C' is
Given below are two statements.
Statement I : Maltose has two $$\alpha$$-D-glucose units linked at C1 and C4 and is a reducing sugar.
Statement II : Maltose has two monosaccharides : $$\alpha$$-D-glucose and $$\beta$$-D-glucose linked at C1 and C6 and it is a non-reducing sugar.
In the light of the above statements, choose the correct answer from the options given below :
Match List I with List II.
List-I (Anion) |
List-II (gas evolved on reaction with dil.H$$_2$$SO$$_2$$) |
||
---|---|---|---|
(A) | CO$${_3^{2 - }}$$ | I. | Colourless gas which turns lead acetate paper black. |
(B) | S$$^{2 - }$$ | II. | Colourless gas which turns acidified potassium dichromate solution green. |
(C) | SO$${_3^{2 - }}$$ | III. | Brown fumes which turns acidified KI solution containing starch blue. |
(D) | NO$${_2^ - }$$ | IV. | Colourless gas evolved with brisk effervescence, which turns lime water milky. |
Choose the correct answer from the options given below :