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JEE Main 2021 (Online) 18th March Evening Shift
Numerical
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10.0 mL of Na2CO3 solution is titrated against 0.2 M HCl solution. The following titre values were obtained in 5 readings :

4.8 mL, 4.9 mL, 5.0 mL, 5.0 mL and 5.0 mL

Based on these readings, and convention of titrimetric estimation the concentration of Na2CO3 solution is ___________ mM.

(Round off to the Nearest Integer).
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2
JEE Main 2021 (Online) 18th March Evening Shift
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The number of species below that have two lone pairs of electrons in their central atom is _________. (Round off to the Nearest Integer).

SF4, BF$$_4^ - $$, ClF3, AsF3, PCl5, BrF5, XeF4, SF6
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3
JEE Main 2021 (Online) 18th March Evening Shift
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JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 112 English
Consider the above reaction where 6.1 g of Benzoic acid is used to get 7.8 g of m-bromo benzoic acid. The percentage yield of the product is __________

(Round off to the Nearest Integer).

[Given : Atomic masses : C : 12.0 u, H : 1.0 u, O : 16.0 u, Br : 80.0 u]
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4
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
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The molar conductivities at infinite dilution of barium chloride, sulphuric acid and hydrochloric acid are 280, 860 and 426 S cm2 mol$$-$$1 respectively. The molar conductivity at infinite dilution of barium sulphate is _________ S cm2 mol$$-$$1. (Round off to the Nearest Integer ).
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