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JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
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JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 97 English
Consider the above reaction, the product 'X' and 'Y' respectively are :
A
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 97 English Option 1
B
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 97 English Option 2
C
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 97 English Option 3
D
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 97 English Option 4
2
JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
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Match List - I with List - II :

List - I
(Class of Chemicals)
List - II
(Example)
(a) Antifertility drug (i) Meprobamate
(b) Antibiotic (ii) Alitame
(c) Tranquilizer (iii) Norethindrone
(d) Artificial Sweetener (iv) Salvarsan


Choose the most appropriate match :
A
(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
B
(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
C
(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
D
(a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
3
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
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-1
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In Tollen's test for aldehyde, the overall number of electron(s) transferred to the Tollen's reagent formula [Ag(NH3)2]+ per aldehyde group to form silver mirror is ___________. (Round off to the Nearest Integer).
Your input ____
4
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
+4
-1
Change Language
10.0 mL of Na2CO3 solution is titrated against 0.2 M HCl solution. The following titre values were obtained in 5 readings :

4.8 mL, 4.9 mL, 5.0 mL, 5.0 mL and 5.0 mL

Based on these readings, and convention of titrimetric estimation the concentration of Na2CO3 solution is ___________ mM.

(Round off to the Nearest Integer).
Your input ____
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