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JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
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JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English
Consider the above reaction, the product 'X' and 'Y' respectively are :
A
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English Option 1
B
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English Option 2
C
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English Option 3
D
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English Option 4
2
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
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In Tollen's test for aldehyde, the overall number of electron(s) transferred to the Tollen's reagent formula [Ag(NH3)2]+ per aldehyde group to form silver mirror is ___________. (Round off to the Nearest Integer).
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3
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
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10.0 mL of Na2CO3 solution is titrated against 0.2 M HCl solution. The following titre values were obtained in 5 readings :

4.8 mL, 4.9 mL, 5.0 mL, 5.0 mL and 5.0 mL

Based on these readings, and convention of titrimetric estimation the concentration of Na2CO3 solution is ___________ mM.

(Round off to the Nearest Integer).
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4
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
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The number of species below that have two lone pairs of electrons in their central atom is _________. (Round off to the Nearest Integer).

SF4, BF$$_4^ - $$, ClF3, AsF3, PCl5, BrF5, XeF4, SF6
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