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1
JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
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An organic compound "A" on treatment with benzene sulphonyl chloride gives compound B. B is soluble in dil. NaOH solution. Compound A is :
A
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Compounds Containing Nitrogen Question 168 English Option 1
B
C6H5 $$-$$ NHCH2CH3
C
C6H5 $$-$$ N $$-$$ (CH3)2
D
C6H5 $$-$$ CH2NHCH3
2
JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
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Main products formed during a reaction of 1-methoxy naphthalene with hydroiodic acid are :
A
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Haloalkanes and Haloarenes Question 110 English Option 1
B
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Haloalkanes and Haloarenes Question 110 English Option 2
C
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Haloalkanes and Haloarenes Question 110 English Option 3
D
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Haloalkanes and Haloarenes Question 110 English Option 4
3
JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
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JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 173 English
Consider the above reaction, the product 'X' and 'Y' respectively are :
A
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 173 English Option 1
B
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 173 English Option 2
C
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 173 English Option 3
D
JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 173 English Option 4
4
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
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-1
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In Tollen's test for aldehyde, the overall number of electron(s) transferred to the Tollen's reagent formula [Ag(NH3)2]+ per aldehyde group to form silver mirror is ___________. (Round off to the Nearest Integer).
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