1
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A shown in the figure, a battery of emf $$\varepsilon $$ is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tc (tc is the time constant of the circuit) is : JEE Main 2020 (Online) 8th January Evening Slot Physics - Electromagnetic Induction Question 109 English
A
$${{\varepsilon L} \over {e{R^2}}}$$
B
$${{\varepsilon L} \over {{R^2}}}$$
C
$${{\varepsilon L} \over {{R^2}}}\left( {1 - {1 \over e}} \right)$$
D
$${{\varepsilon R} \over {e{L^2}}}$$
2
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle moves such that its position vector $$\overrightarrow r \left( t \right) = \cos \omega t\widehat i + \sin \omega t\widehat j$$ where $$\omega $$ is a constant and t is time. Then which of the following statements is true for the velocity $$\overrightarrow v \left( t \right)$$ and acceleration $$\overrightarrow a \left( t \right)$$ of the particle :
A
$$\overrightarrow v $$ and $$\overrightarrow a $$ both are perpendicular to $$\overrightarrow r $$
B
$$\overrightarrow v $$ and $$\overrightarrow a $$ both are parallel to $$\overrightarrow r $$
C
$$\overrightarrow v $$ is perpendicular to $$\overrightarrow r $$ and $$\overrightarrow a $$ is directed towards the origin
D
$$\overrightarrow v $$ is perpendicular to $$\overrightarrow r $$ and $$\overrightarrow a $$ is directed away from the origin
3
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
As shown in figure, when a spherical cavity (centered at O) of radius 1 is cut out of a uniform sphere of radius R (centered at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e, on the surface of the cavity. R can be detemined by the equation : JEE Main 2020 (Online) 8th January Evening Slot Physics - Center of Mass and Collision Question 88 English
A
(R2 + R – 1) (2 – R) = 1
B
(R2 – R – 1) (2 – R) = 1
C
(R2 – R + 1) (2 – R) = 1
D
(R2 + R + 1) (2 – R) = 1
4
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A uniform sphere of mass 500 g rolls without slipping on a plane horizontal surface with its centre moving at a speed of 5.00 cm/s. Its kinetic energy is :
A
8.75 × 10–3 J
B
1.13 × 10–3 J
C
8.75 × 10–4 J
D
6.25 × 10–4 J

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