1
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$\overrightarrow a = \widehat i - 2\widehat j + \widehat k$$ and $$\overrightarrow b = \widehat i - \widehat j + \widehat k$$ be two vectors. If $$\overrightarrow c $$ is a vector such that $$\overrightarrow b \times \overrightarrow c = \overrightarrow b \times \overrightarrow a $$ and $$\overrightarrow c .\overrightarrow a = 0$$, then $$\overrightarrow c .\overrightarrow b $$ is equal to
A
$$ - {1 \over 2}$$
B
$$ - {3 \over 2}$$
C
$${1 \over 2}$$
D
-1
2
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The area (in sq. units) of the region

{(x,y) $$ \in $$ R2 : x2 $$ \le $$ y $$ \le $$ 3 – 2x}, is :
A
$${{34} \over 3}$$
B
$${{29} \over 3}$$
C
$${{31} \over 3}$$
D
$${{32} \over 3}$$
3
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The length of the perpendicular from the origin, on the normal to the curve,
x2 + 2xy – 3y2 = 0 at the point (2,2) is
A
$$\sqrt 2 $$
B
$$4\sqrt 2 $$
C
2
D
$$2\sqrt 2 $$
4
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$I = \int\limits_1^2 {{{dx} \over {\sqrt {2{x^3} - 9{x^2} + 12x + 4} }}} $$, then :
A
$${1 \over 16} < {I^2} < {1 \over 9}$$
B
$${1 \over 8} < {I^2} < {1 \over 4}$$
C
$${1 \over 9} < {I^2} < {1 \over 8}$$
D
$${1 \over 6} < {I^2} < {1 \over 2}$$
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