1
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The probabilities of three events A, B and C are given by
P(A) = 0.6, P(B) = 0.4 and P(C) = 0.5.
If P(A$$ \cup $$B) = 0.8, P(A$$ \cap $$C) = 0.3, P(A$$ \cap $$B$$ \cap $$C) = 0.2, P(B$$ \cap $$C) = $$\beta $$
and P(A$$ \cup $$B$$ \cup $$C) = $$\alpha $$, where 0.85 $$ \le \alpha \le $$ 0.95, then $$\beta $$ lies in the interval :
A
[0.35, 0.36]
B
[0.20, 0.25]
C
[0.25, 0.35]
D
[0.36, 0.40]
2
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The centre of the circle passing through the point (0, 1) and touching the parabola
y = x2 at the point (2, 4) is :
A
$$\left( {{6 \over 5},{{53} \over {10}}} \right)$$
B
$$\left( {{3 \over {10}},{{16} \over 5}} \right)$$
C
$$\left( {{{ - 53} \over {10}},{{16} \over 5}} \right)$$
D
$$\left( {{{ - 16} \over 5},{{53} \over {10}}} \right)$$
3
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The common difference of the A.P.
b1, b2, … , bm is 2 more than the common
difference of A.P. a1, a2, …, an. If
a40 = –159, a100 = –399 and b100 = a70, then b1 is equal to :
A
127
B
81
C
–127
D
-81
4
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$\theta = {\pi \over 5}$$ and $$A = \left[ {\matrix{ {\cos \theta } & {\sin \theta } \cr { - \sin \theta } & {\cos \theta } \cr } } \right]$$.

If B = A + A4 , then det (B) :
A
lies in (1, 2)
B
lies in (2, 3).
C
is zero.
D
is one.
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