1
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For a suitably chosen real constant a, let a

function, $$f:R - \left\{ { - a} \right\} \to R$$ be defined by

$$f(x) = {{a - x} \over {a + x}}$$. Further suppose that for any real number $$x \ne - a$$ and $$f(x) \ne - a$$,

(fof)(x) = x. Then $$f\left( { - {1 \over 2}} \right)$$ is equal to :
A
$$ {1 \over 3}$$
B
–3
C
$$ - {1 \over 3}$$
D
3
2
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let z = x + iy be a non-zero complex number such that $${z^2} = i{\left| z \right|^2}$$, where i = $$\sqrt { - 1} $$ , then z lies on the :
A
line, y = –x
B
real axis
C
line, y = x
D
imaginary axis
3
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The area (in sq. units) of the region enclosed
by the curves y = x2 – 1 and y = 1 – x2 is equal to :
A
$${8 \over 3}$$
B
$${4 \over 3}$$
C
$${7 \over 2}$$
D
$${{16} \over 3}$$
4
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
A plane P meets the coordinate axes at A, B and C respectively. The centroid of $$\Delta $$ABC is given to be (1, 1, 2). Then the equation of the line through this centroid and perpendicular to the plane P is :
A
$${{x - 1} \over 1} = {{y - 1} \over 1} = {{z - 2} \over 2}$$
B
$${{x - 1} \over 2} = {{y - 1} \over 1} = {{z - 2} \over 1}$$
C
$${{x - 1} \over 2} = {{y - 1} \over 2} = {{z - 2} \over 1}$$
D
$${{x - 1} \over 1} = {{y - 1} \over 2} = {{z - 2} \over 2}$$
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