1
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For any $$\theta \in \left( {{\pi \over 4},{\pi \over 2}} \right)$$, the expression

$$3{(\cos \theta - \sin \theta )^4}$$$$ + 6{(\sin \theta + \cos \theta )^2} + 4{\sin ^6}\theta $$

equals :
A
13 – 4 cos2$$\theta $$ + 6sin2$$\theta $$cos2$$\theta $$
B
13 – 4 cos6$$\theta $$
C
13 – 4 cos2$$\theta $$ + 6cos2$$\theta $$
D
13 – 4 cos4$$\theta $$ + 2sin2$$\theta $$cos2$$\theta $$
2
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For x2 $$ \ne $$ n$$\pi $$ + 1, n $$ \in $$ N (the set of natural numbers), the integral

$$\int {x\sqrt {{{2\sin ({x^2} - 1) - \sin 2({x^2} - 1)} \over {2\sin ({x^2} - 1) + \sin 2({x^2} - 1)}}} dx} $$ is equal to :

(where c is a constant of integration)
A
$${\log _e}\left| {{1 \over 2}{{\sec }^2}\left( {{x^2} - 1} \right)} \right| + c$$
B
$${1 \over 2}{\log _e}\left| {\sec \left( {{x^2} - 1} \right)} \right| + c$$
C
$${1 \over 2}{\log _e}\left| {{{\sec }^2}\left( {{{{x^2} - 1} \over 2}} \right)} \right| + c$$
D
$${\log _e}\left| {\sec \left( {{{{x^2} - 1} \over 2}} \right)} \right| + c$$
3
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
5 students of a class have an average height 150 cm and variance 18 cm2. A new student, whose height is 156 cm, joined them. The variance (in cm2) of the height of these six students is :
A
16
B
22
C
20
D
18
4
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The maximum volume (in cu.m) of the right circular cone having slant height 3 m is :
A
2$$\sqrt3$$$$\pi $$
B
3$$\sqrt3$$$$\pi $$
C
6$$\pi $$
D
$${4 \over 3}\pi $$

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