1
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For any $$\theta \in \left( {{\pi \over 4},{\pi \over 2}} \right)$$, the expression

$$3{(\cos \theta - \sin \theta )^4}$$$$ + 6{(\sin \theta + \cos \theta )^2} + 4{\sin ^6}\theta $$

equals :
A
13 – 4 cos2$$\theta $$ + 6sin2$$\theta $$cos2$$\theta $$
B
13 – 4 cos6$$\theta $$
C
13 – 4 cos2$$\theta $$ + 6cos2$$\theta $$
D
13 – 4 cos4$$\theta $$ + 2sin2$$\theta $$cos2$$\theta $$
2
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For $$x \in R - \left\{ {0,1} \right\}$$, Let f1(x) = $$1\over x$$, f2 (x) = 1 – x

and f3 (x) = $$1 \over {1 - x}$$ be three given

functions. If a function, J(x) satisfies

(f2 o J o f1) (x) = f3 (x) then J(x) is equal to :
A
f1 (x)
B
$$1 \over x$$ f3 (x)
C
f2 (x)
D
f3 (x)
3
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The equation of the line passing through (–4, 3, 1), parallel

to the plane x + 2y – z – 5 = 0 and intersecting

the line $${{x + 1} \over { - 3}} = {{y - 3} \over 2} = {{z - 2} \over { - 1}}$$ is :
A
$${{x + 4} \over 3} = {{y - 3} \over {-1}} = {{z - 1} \over 1}$$
B
$${{x + 4} \over 1} = {{y - 3} \over {1}} = {{z - 1} \over 3}$$
C
$${{x + 4} \over -1} = {{y - 3} \over {1}} = {{z - 1} \over 1}$$
D
$${{x - 4} \over 2} = {{y + 3} \over {1}} = {{z + 1} \over 4}$$
4
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
Equation of a common tangent to the circle, x2 + y2 – 6x = 0 and the parabola, y2 = 4x is :
A
$$2\sqrt 3 $$y = 12x + 1
B
$$\sqrt 3 $$y = x + 3
C
$$2\sqrt 3 $$y = -x - 12
D
$$\sqrt 3 $$y = 3x + 1
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