1
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The element having greatest difference between its first and second ionization energies, is :
A
Ba
B
Ca
C
Sc
D
K
2
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For any given series of spectral lines of atomic hydrogen, let $$\Delta \mathop v\limits^\_ = $$ $$\Delta {\overline v _{\max }} - \Delta {\overline v _{\min }}$$ be the difference in maximum and minimum frequencies in cm–1. The ratio Lyman Balmer $${{\Delta {{\overline v }_{Lyman}}} \over {\Delta {{\overline v }_{Balmer}}}}$$ is :
A
9 : 4
B
4 : 1
C
27 : 5
D
5 : 4
3
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product of the following reaction is :
JEE Main 2019 (Online) 9th April Morning Slot Chemistry - Hydrocarbons Question 96 English
A
CH3CD2CH(Cl)(I)
B
CH3CD(Cl)CHD(I)
C
CH3C(I)(Cl)CHD2
D
CH3CD(I)CHD(Cl)
4
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$\overrightarrow \alpha = 3\widehat i + \widehat j$$ and $$\overrightarrow \beta = 2\widehat i - \widehat j + 3 \widehat k$$ . If $$\overrightarrow \beta = {\overrightarrow \beta _1} - \overrightarrow {{\beta _2}} $$, where $${\overrightarrow \beta _1}$$ is parallel to $$\overrightarrow \alpha $$ and $$\overrightarrow {{\beta _2}} $$ is perpendicular to $$\overrightarrow \alpha $$ , then $${\overrightarrow \beta _1} \times \overrightarrow {{\beta _2}} $$ is equal to
A
$$ 3\widehat i - 9\widehat j - 5\widehat k$$
B
$${1 \over 2}$$($$ - 3\widehat i + 9\widehat j + 5\widehat k$$)
C
$$ - 3\widehat i + 9\widehat j + 5\widehat k$$
D
$${1 \over 2}$$($$ 3\widehat i - 9\widehat j + 5\widehat k$$)
JEE Main Papers
2023
2021
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
CBSE
Class 12