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1
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Slope of a line passing through P(2, 3) and intersecting the line, x + y = 7 at a distance of 4 units from P, is :
A
$${{\sqrt 7 - 1} \over {\sqrt 7 + 1}}$$
B
$${{\sqrt 5 - 1} \over {\sqrt 5 + 1}}$$
C
$${{1 - \sqrt 5 } \over {1 + \sqrt 5 }}$$
D
$${{1 - \sqrt 7 } \over {1 + \sqrt 7 }}$$
2
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The solution of the differential equation

$$x{{dy} \over {dx}} + 2y$$ = x2 (x $$ \ne $$ 0) with y(1) = 1, is :
A
$$y = {4 \over 5}{x^3} + {1 \over {5{x^2}}}$$
B
$$y = {3 \over 4}{x^2} + {1 \over {4{x^2}}}$$
C
$$y = {{{x^2}} \over 4} + {3 \over {4{x^2}}}$$
D
$$y = {{{x^3}} \over 5} + {1 \over {5{x^2}}}$$
3
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$\sum\limits_{k = 1}^{10} {f(a + k) = 16\left( {{2^{10}} - 1} \right)} $$ where the function ƒ satisfies
ƒ(x + y) = ƒ(x)ƒ(y) for all natural numbers x, y and ƒ(1) = 2. then the natural number 'a' is
A
2
B
16
C
4
D
3
4
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$\alpha $$ and $$\beta $$ be the roots of the equation x2 + x + 1 = 0. Then for y $$ \ne $$ 0 in R,
$$$\left| {\matrix{ {y + 1} & \alpha & \beta \cr \alpha & {y + \beta } & 1 \cr \beta & 1 & {y + \alpha } \cr } } \right|$$$ is equal to
A
y(y2 – 1)
B
y(y2 – 3)
C
y3
D
y3 – 1

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