1
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The integral $$\int {{\rm{se}}{{\rm{c}}^{{\rm{2/ 3}}}}\,{\rm{x }}\,{\rm{cose}}{{\rm{c}}^{{\rm{4 / 3}}}}{\rm{x \,dx}}} $$ is equal to (Hence C is a constant of integration)
A
-3/4 tan - 4 / 3 x + C
B
3tan–1/3x + C
C
–3cot–1/3x+ C
D
- 3tan–1/3x + C
2
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\left[ {\matrix{ 1 & 1 \cr 0 & 1 \cr } } \right]\left[ {\matrix{ 1 & 2 \cr 0 & 1 \cr } } \right]$$$$\left[ {\matrix{ 1 & 3 \cr 0 & 1 \cr } } \right]$$....$$\left[ {\matrix{ 1 & {n - 1} \cr 0 & 1 \cr } } \right] = \left[ {\matrix{ 1 & {78} \cr 0 & 1 \cr } } \right]$$,

then the inverse of $$\left[ {\matrix{ 1 & n \cr 0 & 1 \cr } } \right]$$ is
A
$$\left[ {\matrix{ 1 & { 0} \cr {12} & 1 \cr } } \right]$$
B
$$\left[ {\matrix{ 1 & { 0} \cr {13} & 1 \cr } } \right]$$
C
$$\left[ {\matrix{ 1 & { - 13} \cr 0 & 1 \cr } } \right]$$
D
$$\left[ {\matrix{ 1 & { - 12} \cr 0 & 1 \cr } } \right]$$
3
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Slope of a line passing through P(2, 3) and intersecting the line, x + y = 7 at a distance of 4 units from P, is :
A
$${{\sqrt 7 - 1} \over {\sqrt 7 + 1}}$$
B
$${{\sqrt 5 - 1} \over {\sqrt 5 + 1}}$$
C
$${{1 - \sqrt 5 } \over {1 + \sqrt 5 }}$$
D
$${{1 - \sqrt 7 } \over {1 + \sqrt 7 }}$$
4
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The solution of the differential equation

$$x{{dy} \over {dx}} + 2y$$ = x2 (x $$ \ne $$ 0) with y(1) = 1, is :
A
$$y = {4 \over 5}{x^3} + {1 \over {5{x^2}}}$$
B
$$y = {3 \over 4}{x^2} + {1 \over {4{x^2}}}$$
C
$$y = {{{x^2}} \over 4} + {3 \over {4{x^2}}}$$
D
$$y = {{{x^3}} \over 5} + {1 \over {5{x^2}}}$$

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