1
JEE Main 2019 (Online) 10th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the area of an equilateral triangle inscribed in the circle x2 + y2 + 10x + 12y + c = 0 is $$27\sqrt 3 $$ sq units then c is equal to :
A
20
B
25
C
$$-$$ 25
D
13
2
JEE Main 2019 (Online) 10th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The length of the chord of the parabola x2 $$=$$ 4y having equation x – $$\sqrt 2 y + 4\sqrt 2 = 0$$  is -
A
$$8\sqrt 2 $$
B
$$6\sqrt 3 $$
C
$$3\sqrt 2 $$
D
$$2\sqrt {11} $$
3
JEE Main 2019 (Online) 10th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let N be the set of natural numbers and two functions f and g be defined as f, g : N $$ \to $$ N such that

f(n) = $$\left\{ {\matrix{ {{{n + 1} \over 2};} & {if\,\,n\,\,is\,\,odd} \cr {{n \over 2};} & {if\,\,n\,\,is\,\,even} \cr } \,\,} \right.$$;

      and g(n) = n $$-$$($$-$$ 1)n.

Then fog is -
A
neither one-one nor onto
B
onto but not one-one
C
both one-one and onto
D
one-one but not onto
4
JEE Main 2019 (Online) 10th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two identical spherical balls of mass M and radius R each are stuck on two ends of a rod of length 2R and mass M (see figure). The moment of inertia of the system about the axis passing perpendicularly through the centre of the rod is :

JEE Main 2019 (Online) 10th January Evening Slot Physics - Rotational Motion Question 185 English
A
$${{17} \over {15}}$$ MR2
B
$${{137} \over {15}}$$ MR2
C
$${{209} \over {15}}$$ MR2
D
$${{152} \over {15}}$$ MR2
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