1
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product of the following reaction is :

JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 137 English
A
JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 137 English Option 1
B
JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 137 English Option 2
C
JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 137 English Option 3
D
JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 137 English Option 4
2
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The reagent(s) required for the following conversion are :

JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 199 English
A
(i) B2H6;    (ii) SnCl2/HCl;    (iii) H3O+
B
(i) LiAlH4;   (ii) H3O+  
C
(i) B2H6;   (ii) DIBALH;   (iii) H3O+
D
(i) NaBH4;   (ii) Raney Ni/H2;    (iii) H3O+
3
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider the following two binary relations on the set A = {a, b, c} :
R1 = {(c, a), (b, b), (a, c), (c, c), (b, c), (a, a)} and
R2 = {(a, b), (b, a), (c, c), (c, a), (a, a), (b, b), (a, c)}.
Then :
A
both R1 and R2 are not symmetric.
B
R1 is not symmetric but it is transitive.
C
R2 is symmetric but it is not transitive.
D
both R1 and R2 are transitive.
4
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\lambda $$ $$ \in $$ R is such that the sum of the cubes of the roots of the equation,
x2 + (2 $$-$$ $$\lambda $$) x + (10 $$-$$ $$\lambda $$) = 0 is minimum, then the magnitude of the difference of the roots of this equation is :
A
$$4\sqrt 2 $$
B
$$2\sqrt 5 $$
C
$$2\sqrt 7 $$
D
20
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