1
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let y = y(x) be the solution of the differential equation $${{dy} \over {dx}} + 2y = f\left( x \right),$$

where $$f\left( x \right) = \left\{ {\matrix{ {1,} & {x \in \left[ {0,1} \right]} \cr {0,} & {otherwise} \cr } } \right.$$

If y(0) = 0, then $$y\left( {{3 \over 2}} \right)$$ is :
A
$${{{e^2} + 1} \over {2{e^4}}}$$
B
$${1 \over {2e}}$$
C
$${{{e^2} - 1} \over {{e^3}}}$$
D
$${{{e^2} - 1} \over {2{e^3}}}$$
2
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
A circle passes through the points (2, 3) and (4, 5). If its centre lies on the line, $$y - 4x + 3 = 0,$$ then its radius is equal to :
A
2
B
$$\sqrt 5 $$
C
$$\sqrt 2 $$
D
1
3
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the tangents drawn to the hyperbola 4y2 = x2 + 1 intersect the co-ordinate axes at the distinct points A and B then the locus of the mid point of AB is :
A
x2 $$-$$ 4y2 + 16x2y2 = 0
B
x2 $$-$$ 4y2 $$-$$ 16x2y2 = 0
C
4x2 $$-$$ y2 + 16x2y2 = 0
D
4x2 $$-$$ y2 $$-$$ 16x2y2 = 0
4
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
Two parabolas with a common vertex and with axes along x-axis and $$y$$-axis, respectively intersect each other in the first quadrant. If the length of the latus rectum of each parabola is $$3$$, then the equation of the common tangent to the two parabolas is :
A
4(x + y) + 3 = 0
B
3(x + y) + 4 = 0
C
8(2x + y) + 3 = 0
D
x + 2y + 3 = 0
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