1
JEE Main 2020 (Online) 3rd September Evening Slot
Numerical
+4
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The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is ___________.
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2
JEE Main 2020 (Online) 3rd September Evening Slot
Numerical
+4
-0
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6.023 $$ \times $$ 1022 molecules are present in 10 g of a substance 'x'. The molarity of a solution containing 5 g of substance 'x' in 2 L solution is _____ × 10-3
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3
JEE Main 2020 (Online) 3rd September Morning Slot
Numerical
+4
-0
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The mole fraction of glucose (C6H12O6 ) in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is _______.
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4
JEE Main 2020 (Online) 3rd September Morning Slot
Numerical
+4
-0
Change Language
The volume strength of 8.9 M H2O2 solution calculated at 273 K and 1 atm is ______. (R = 0.0821 L atm K-1 mol-1) (rounded off ot the nearest integer)
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