1
JEE Main 2021 (Online) 26th February Evening Shift
Numerical
+4
-1
The NaNO3 weighed out to make 50 mL of an aqueous solution containing 70.0 mg Na+ per mL is _________ g. (Rounded off to the nearest integer)

[Given : Atomic weight in g mol$$-$$1 - Na : 23; N : 14; O : 16]
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2
JEE Main 2021 (Online) 26th February Morning Shift
Numerical
+4
-1
The number of significant figures in 50000.020 $$\times$$ 10$$-$$3 is _____________.
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3
JEE Main 2021 (Online) 25th February Morning Slot
Numerical
+4
-1
In basic medium $$Cr{O_4}^{2 - }$$ oxidises $${S_2}{O_3}^{2 - }$$ to form $$S{O_4}^{2 - }$$ and itself changes into $$Cr{(OH)_4}^ - $$. The volume of 0.154 M $$Cr{O_4}^{2 - }$$ required to react with 40 mL of 0.25 M $${S_2}{O_3}^{2 - }$$ is __________ mL. (Rounded off to the nearest integer)
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4
JEE Main 2021 (Online) 24th February Evening Slot
Numerical
+4
-1
Change Language
The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O2 for complete oxidation and produces 4 times its own volume of CO2 is CxHy. The value of y is _____________.
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