1

### JEE Main 2016 (Online) 9th April Morning Slot

The test to distinguish primary, secondary and tertiary amines is :
A
Carbylamine reaction
B
C6H5SO2Cl
C
Sandmeyer’s reaction
D
Mustard oil test

## Explanation

Hinsberg’s reagent (C6H5SO2Cl) forms monoalkyl sulphonamide with 1o amines which is soluble in KOH. With 2o amines it gives dialkyl sulphonamide which is insoluble in KOH and with 3o amines there is no reaction.

In mustard oil test, 1o amines on action of CS2 and HgCl2 give alkyl isothiocyanate having mustard oil smell. 2o amines react with CS2 but not with HgCl2 while 3o amines give no reaction. However, this test is not able to distinguish 2o and 3o amines.
2

### JEE Main 2016 (Online) 10th April Morning Slot

Fluorination of an aromatic ring is easily accomplished by treating a diazonium salt with HBF4. Which of the following conditions is correct about this reaction ?
A
Only heat
B
NaNO2/Cu
C
Cu2O/H2O
D
NaF/Cu

## Explanation

3

### JEE Main 2016 (Online) 10th April Morning Slot

The “N” which does not contribute to the basicity for the compound is :

A
N 7
B
N 9
C
N 1
D
N 3

## Explanation

In this aromatic compound, the lone of N9 is participate in resonance with the compound and complete the aromatic system. So this lone pair is delocalised and can not gain proton (H+)

When an atom is already part of $\pi$ bond then the lone pair of the atom can not participate in resonance. That lone pair is called localised lone pair.

Here in N1, N3 and N7 all the lone pairs are localised. As those lone pair do not participate in resonance so it can gain proton (H+) so those lone pair will increase the basicity of the compound.
4

### JEE Main 2017 (Offline)

Which of the following compounds will form significant amount of meta product during mono-nitration reaction?
A
B
C
D

## Explanation

Nitration takes place in presence of concentrated HNO3 + concentrated H2SO4.

In strongly acidic nitration medium, the amine is converted into anilinium ion (– NH3+ ); substitution is thus controlled not by – NH2 group but by – NH3+ group which, because of its positive charge, directs the entering group to the meta-position instead of ortho and para.